2y^2+8y+6=0*

Solution for 2y^2+8y+6=0* equation:

2y^2+8y+6=0*

We move all terms to the left:

2y^2+8y+6-(0*)=0

We add all the numbers together, and all the variables

2y^2+8y+6-0=0

We add all the numbers together, and all the variables

2y^2+8y+6=0

a = 2; b = 8; c = +6;
Δ = b2-4ac
Δ = 82-4·2·6
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*2}=\frac{-12}{4}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*2}=\frac{-4}{4}
=-1
$